Goroutine

go语言可以很轻松的实现并发获取数据，就算是新手也可以按部就班的套用现成的并发模式来实现并发。以下是一个简单的测试程序，其中有串行，并行。

package main

import (
	"sync"
	"time"
	"fmt"
)
func main() {
	syncFunc()
	fmt.Println(">>>>>>>>>>>>>>>")
	asyncFunc()
	fmt.Println(">>>>>>>>>>>>>>>")
	asyncChanFunc()
}
// 串行执行
func syncFunc() {
	var n,m,x int
	start := time.Now()
	fmt.Println("syncFunc start:",start)
	func () {
		time.Sleep(time.Second*1)
		n = 1
	}()
	func () {
		time.Sleep(time.Second*2)
		m = 2
	}()
	func () {
		time.Sleep(time.Second*3)
		x  =3
	}()
	t := time.Now()
	fmt.Println(t)
	elapsed := t.Sub(start)
	fmt.Println("syncFunc end:", elapsed, n, m, x)
}
// 并行执行
func asyncFunc() {
	var n,m,x int
	var wg sync.WaitGroup
	wg.Add(3)
	start := time.Now()
	fmt.Println("asyncFunc start:", start)
	go func () {
		defer wg.Done()
		time.Sleep(time.Second*1)
		n = 1
	}()
	go func () {
		defer wg.Done()
		time.Sleep(time.Second*2)
		m = 2
	}()
	go func () {
		defer wg.Done()
		time.Sleep(time.Second*3)
		x = 3
	}()
	wg.Wait()
	t := time.Now()
	fmt.Println(t)
	elapsed := t.Sub(start)
	fmt.Println("asyncFunc end:", elapsed, n, m, x)
}

// 并行执行
func asyncChanFunc() {
	var n, m, x =make(chan int),make(chan int),make(chan int)
	start := time.Now()
	fmt.Println("asyncChanFunc start:",start)
	go func () {
		time.Sleep(time.Second*1)
		n <- 1
	}()
	go func () {
		time.Sleep(time.Second*2)
		m <- 2
	}()
	go func () {
		time.Sleep(time.Second*3)
		x <- 3
	}()

	fmt.Printf("n:%d, m:%d, x:%d\n",<-n, <-m, <-x)
	t := time.Now()
	fmt.Println(t)
	elapsed := t.Sub(start)
	fmt.Println("asyncChanFunc end:", elapsed)
}

测试结果：